How to split with awk escaping all special characters

I want to use only the first column and divide each line into 4 columns: #CHROM POS REF ALT 1 10203040 TC 1 10203050 TA 1 10203060 AG 1

You can set field-separator using -F option. Use the following commands in terminal, $ awk -F :: 'NR==1 {print $1}' logfile.txt 1 $ awk -F ...

The 'split' function in AWK is a powerful tool that allows you to divide a string into pieces based on a specified delimiter.

To split a string to an array in awk we use the function split(): awk '{split($0, array, :)}' # -/ -___/ -_/ # | | | # string | delimiter # | # array to ...

Split function in (g)awk is meant to split a string on delimiters. It populates an array with fields that are delimited by the delimiter.

I want the awk script to show: User is NIR, SHELL is BASH User is ABI, SHELL is SH I don't know how to split a parameter by char.

I'm trying to create a char array by using split, it works so far. The problem is when any character in the input string is preceded by -.

In this tutorial, we'll explore multiple strategies to split a parameter (input record) by a character using awk.

I want to split a string in awk and treat each component seperatley. I know i can use: Code: split (hi all, a, ) to put each delimited component into ...